Hi Ryan I have another physics question, this time it is to do with heat transfer.Consider a copper pipe (1M length) covered with an asbestos layer and finally a fibreglass layer. The radius of the copper pipe is 0.025m, the radius of the asbestos layer from the centre of the copper pipe is 0.03M, the radius of the fibre glass layer from the centre of the copper pipe is 0.055M. The temperature of the copper pipe surface and interface with the asbestos layer is 100C, the temperature of the outside surface of the fibre glass layer is 30C. Calculate the the temperature at the asbestos fibre glass interface.(Hint: R total = R rad, asbestos + R rad, Fibre Glass)K asbestos = 0.15 W/(m C) , K Fibre Glass = 0.04 W/(m C) I need to know the equation to use and any transposition of the equation and the solution
I have an equation but need to know delta T in order to use the equation to find the heat transfer
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B.S. in Civil Engineering