Need someone who has a good knowledge of physics to help me with these problems please!! (See attached word doc file). If you want to split them up into two sections, that is fine. However, I need assistance with these by 4pm EST (USA) 5.28.2012 Need some help please A. A man steps on his bathroom scale and obtains a reading of 243 lb. The spring in the scale is compressed by a displacement of -0.0570 inches. Calculate the value of its spring constant in (a) pounds per inch (b) newtons per meterB. An ice rescue team pulls a stranded hiker off a frozen lake by throwing him a rope and pulling him horizontally across the essentially frictionless ice with a constant force. The hiker weighs 1040 N, and accelerates across the ice at 1.15 m/s2. What is the magnitude of the tension in the rope? (Ignore the mass of the rope.)C. A 22.0 kg child slides down a slide that makes a 37.0° angle with the horizontal. (a) What is the magnitude of the normal force that the slide exerts on the child? (b) At what angle from the horizontal is this force directed? State your answer as a number between 0 and 90°.D. A cup and saucer rest on a table top. The cup has mass 0.176 kg and the saucer 0.165 kg. Calculate the magnitude of the normal force (a) the saucer exerts on the cup and (b) the table exerts on the saucer.E. A 7.6 kg chair is pushed across a frictionless floor with a force of 42 N that is applied at an angle of 22° downward from the horizontal. What is the magnitude of the acceleration of the chair?F. There are two forces acting on a box of golf balls, F1 and F2. The mass of the box is 0.750 kg. When the forces act in the same direction, they cause an acceleration of 0.450 m/s2. When they oppose one another, the box accelerates at 0.240 m/s2 in the direction of F2. (a) What is the magnitude of F1? (b) What is the magnitude of F2?G. A giant excavator (used in road construction) can apply a maximum vertical force of 2.25×105 N. If it can vertically accelerate a load of dirt at 0.200 m/s2, what is the mass of that load? Ignore the mass of the excavator itself.H. A flea has a mass of 4.9×10−7 kg. When a flea jumps, its rear legs act like catapults, accelerating it at 2400 m/s2. What force do the flea's legs have to exert on the ground for a flea to accelerate at this rate?I. Three children are pulling on a toy that has a mass of 1.25 kg. Child A pulls with force (5.00, 6.00, 2.50) N. Child B pulls with force (0.00, 9.20, 2.40) N. With what force must Child C pull for the toy to remain stationary?
Hi,Thank you for using JustAnswer.I can have these posted for you by morning. (By the way, I haven't forgotten about the previous set. I have them done, I just need to type them up.)Thanks,Ryan
Oh wow, thanks! I've been all afternoon trying to figure these out so I didn't have to ask for help. I just honestly can't get them! :( I think I need a different text book. Do you know of a good one that is easy to understand?
Hi,The only physics book that I have is Fundamentals of Physics, by Halliday and Resnick. I didn't have much of a choice as it was the required textbook for my physics courses, but I liked it. I don't know that it would qualify as "easy to understand" though, that's a pretty subjective assessment.I think that a lot of students find physics challenging because it's almost all word problems, which most students have been trying to avoid since the beginning of algebra. There aren't many problem where you can just "plug and chug" like there are in algebra. Physics is more of an applied math course.I'll write up the solutions for these as soon as I can, and if you have any questions about them I'll be happy to explain anything that is unclear.(By the way, I'll be posting the first part of the other set just as soon as I post this.)Thanks,Ryan
Hi,Here are the solutions for the first five:Solutions3Thanks,Ryan
THIS ANSWER IS LOCKED!You can view this answer by clicking here to Register or Login and paying $3. If you've already paid for this answer, simply Login.
Thank you so much, I will try and find that text book you mentioned asap. Hopefully it will help me understand better.
Hi,You're quite welcome. I'm glad that I could help.Thanks,Ryan