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Statistic formula needed to solve the follow question need help ASAP!I've done research and need an hypothesis statistic test calculated and COMPUTE PROBABILITY OF TEST STATISTIC OR REJECTION REGION.Here is my research along with my hypothesis' alternative and nullProblem QuestionWill insects vacate a porch, primarily wasps if the ceiling is painted sky blue?Alternative HypothesisPainting a ceiling sky blue will deter insects from building nests on the porch.Null HypothesisSky blue ceiling doesn’t deter insects from building nests on the porch.Prediction If a porch ceiling or any other is painted blue, then insects would still build nests at the same degree as they would do with any other color.Controlled Experimentation Method Fifteen houses with similar designs were selected in a large southern suburban neighborhood. Seven paints with different colors – one of them being sky blue with one other being an outdated sky blue milk paint containing lye. All paints except for the milk paint were purchased from the same manufacturer which should ascertain that no difference arises due to chemical composition of the paint. With owners’ permission, porch ceiling of five randomly selected houses were painted with sky blue. Congruently on the same side of the rode and additional five randomly selected houses were painted with sky blue milk paint. Porch ceilings in each of the remaining five houses were painted with one of the five leftover colors. After two years, porches were observed for number of wasp nests.Results Following number of wasp nests were observed in porchesPorches with blue-colored ceiling – 0, 2, 3, 1, 1Porches with milk paint blue-colored ceiling – 0, 0, 1, 2, 2Porches with other color ceiling – 3, 2, 2, 1, 1A hypothesis test was conducted to find if statistically significant difference existed between two group means.
Hi,I see 3 groups at the endTell me the 2 groups where you need the testSteve
Would you do the test twice. Line 1 vs. Line 3, and Line 2 vs. Line 3?
OK,so you wantTest 1)Porches with blue-colored ceiling – 0, 2, 3, 1, 1vsPorches with other color ceiling – 3, 2, 2, 1, 1AndTest 2)Porches with milk paint blue-colored ceiling – 0, 0, 1, 2, 2vsPorches with other color ceiling – 3, 2, 2, 1, 1Steve
yes please
Ok,I am working on them, i will put the first test soonSteve
ok thank you.
Test 1)Porches with blue-colored ceiling – 0, 2, 3, 1, 1vsPorches with other color ceiling – 3, 2, 2, 1, 1Ho: u1=u2Ha: u1≠u2x-bar-1= 1.4x-bar-2 =0.942sd1=1.14sd2=0.837(sp)^2 = [(5-1)(sd1)^2+(5-1)(sd2)^2]/(10-2)=1.000042249Statistic = t = (1.14-0.837)/sp√(1/5+1/5) =0.724Critical values: -t(0.025,8)= -2.306 and t(0.025,8)=2.306Critical region: {t/t<-2.306 or t>2.306}Decision: Since the statistic value does not fails into the critical regionwe do not reject HoThanksSteve
Experience: I teach Calculus and Probability in a University since 1994
Test one looks great thanks!
Ok,I will post the second one in a moment, can you accept the previous one ?Steve
10-4 first one is accepted
Ok,I am working on the second testSteve
I had some mistakes with test 1)I will fix it nowSteve
ok
Test 1)Porches with blue-colored ceiling – 0, 2, 3, 1, 1vsPorches with other color ceiling – 3, 2, 2, 1, 1Ho: u1=u2Ha: u1≠u2x-bar-1= 1.4x-bar-2 =1.8sd1=1.14sd2=0.837(sp)^2 = [(5-1)(sd1)^2+(5-1)(sd2)^2]/(10-2)=1.000042249Statistic = t = (1.4-1.8)/sp√(1/5+1/5) =-0.632Critical values: -t(0.025,8)= -2.306 and t(0.025,8)=2.306Critical region: {t/t<-2.306 or t>2.306}Decision: Since the statistic value does not fails into the critical regionwe do not reject HoThanksSteve
I am working on the second nowSteve
When the second one is done I will add an additional bonus that wasn't added into the first accept
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