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Can somebody help me with chem 213 ; I have a question about

Customer Question

Can somebody help me with chem 213 ; I have a question about NMR spectroscopy.
Thea Smith
Submitted: 4 years ago.
Category: Homework
Expert:  Academic Tutor replied 4 years ago.
Go ahead and ask, e6wr8dpm,

One of us should be able to answer it.
Customer: replied 4 years ago.

Give the structure that corresponds to the following molecular formula and 1H NMR spectrum: C4H10O2: δ 1.36 (3H, d, J = 5.5 Hz); δ 3.32 (6H, s); δ 4.63 (1H, q, J = 5.5 Hz)
Give the structure that corresponds to the following molecular formula and 1H NMR spectrum: C7H12Cl2: δ 1.07 (integral = 6203, s); δ 2.28 (integral = 1402, d, J = 6 Hz); δ 5.77 (integral = 700, t, J = 6 Hz). Note: The integrals are given in arbitrary units.
Give the structure that corresponds to the following molecular formula and NMR spectra: C6H14O      1H NMR: δ 0.91 (6H, d, J = 7 Hz); δ 1.17 (6H, s); δ 1.48 (1H, s; disappears after D2O shake); δ 1.65 (1H, septet, J = 7 Hz).      13C NMR: δ 17.6, δ 26.5, δ 38.7, δ 73.2.
Give the structure that corresponds to the following molecular formula and 1H NMR spectrum: C7H16O4: δ 1.93 (t, J = 6 Hz); δ 3.35 (s); δ 4.49 (t, J = 6 Hz); relative integral 1:6:1.
Identify the following compound from its IR and proton NMR spectra. C6H10O: NMR: δ 3.31 (3H, s); δ 2.41 (1H, s); δ 1.43 (6H, s) IR: 2110, 3300 cm–1 (sharp)
Identify the following compound from its IR and proton NMR spectra. C5H6O: IR: 3300 (sharp), 2102, 1634 cm–1 NMR: δ 3.10 (1H, d, J = 2 Hz); δ 3.79 (3H, s); δ 4.52 (1H, doublet of doublets, J = 6 Hz and 2 Hz); δ 6.38 (1H, d, J = 6 Hz)
Identify the following compound. C10H10O2: NMR: δ 2.82 (6H, s), δ 8.13 (4H, s) IR: 1681 cm–1, no O–H stretch.
Expert:  Academic Tutor replied 4 years ago.
Beautiful,

Now that we can see the question, I will let one of the experts that specializes in chem answer. So I will just drop out.
Expert:  Angela--Mod replied 4 years ago.
Hi, I’m a moderator for this topic and I wonder whether you’re still waiting for an answer. If you are, please let me know and I will do my best to find another Expert to assist you right away. If not, feel free to let me know and I will cancel this question for you. Thank you!

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