Answers are given in bold below each question.
Write the vector v in the form v1i + v2j given || v|| and the angle that v makes with the positive x axis.
||v|| = 29, 0= 4pi/3 v= (?) I + (?) j
Simplify answer. Type an exact answer, using radicals as needed. Use integers or fractions for any numbers in the expression.
V = v1i+v2j = 29 cos (4π/3)i+29sin(4π/3)j
Find the magnitude and direction angle 0 of the vector.
U=2[(cos 198 degree)I _ (sin 198) j]
The magnitude is ? and the direction angle is ?
Magnitude = 2; angle = -1980
The magnitude and direction of two forces acting on an object are 70lbs, S70E, and 110 pounds N59E, respectively. Find the magnitude to the nearest hundredth of a pound, and the direction angle, to the nearest tenth of a degree of the resultant force.
The magnitude is approximately ? bls. (do not round until the final answer. Then round to the nearest hundredth as needed)
Let F1 = 110lbs N59E and F2 = 70lbsS70E
F1 = 110cos31i+110sin31j = 94.29i+56.65j (angle with +ve x-axis is 31degrees)
F2 = 70cos20i-70sin20j = 65.78i-25.09j (angle with +ve x-axis is -20degrees)
Hence, resultant = F1+F2 = 160.07i+31.57j = 163.15 and angle 11.160
Or, 163.15 N78.840E
4. A weight of 1700 lbs is suspended from two cables as shown in the figure. What is the tension in the two cables?
Round to one decimal place as needed.
The figure is required for solving this problem.
Kindly ACCEPT the answers.