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n ≥ p(1 - p)(z/E)^2
substitute p = 0.1
z = 2.576
E = 0.015
n ≥ 0.1(1 - 0.1)(2.576/0.015)^2
n ≥ 2654.3
round it up to the next integer,
n = 2655
Margin of Error = z*sqrt(p(1 - p)/n)
The sample size is required to answer this part of the question.
ok how can i find the sample size
It should be given in the question.
Unless the question is asking us to use the sample size we found in part A.
It doesn't say so but it could be.
thats where i got stuck
If so then the margin of error doesn't change.
It is 0.015