Experts are full of valuable knowledge and are ready to help with any question. Credentials confirmed by a Fortune 500 verification firm.

Get a Professional Answer

Via email, text message, or notification as you wait on our site. Ask follow up questions if you need to.

100% Satisfaction Guarantee

Rate the answer you receive.

Ask R.R. Jha Your Own Question

R.R. Jha, Tutor

Category: Homework

Satisfied Customers: 5380

Experience: B.Tech

Type Your Homework Question Here...

R.R. Jha is online now

Sketch a position vs time graph, a velocity vs time graph

Customer Question

Sketch a position vs time graph, a velocity vs time graph and an acceleration vs time graph for a bus traveling west and speeding up. If you cannot sketch it just describe it in detail that would be fine. For example you can say on the X axis is displacement and time on yaxis and the graph will be a line starting from 0,0 and going down (in south east direction) at a constant slope etc..

I'd assume time on x-axis and other variable on y-axis. Let the acceleration of the bus be 'α'. If the acceleration is constant, α is constant, and the equations for acceleration, velocity and displacement are

a = α (horizontal line cutting y axis at y=α) v = u + αt (straight line with slope α, and cutting y-axis at y=u) x = ut + ½ αt² (parabola)

Where u is the initial velocity of the bus at t=0. Assuming u=1, α=1, the plots are as below Acceleration

Attachments are only available to registered users.

Hi.. In the school (in the west) traveling west is graphed in the negative corodinates (up and East is positive) down and west is negative. Hence the graphs as shown above would not be correct. If you do not have exposure to this way of teaching then this may not a be a question you would like to attempt.

THIS ANSWER IS LOCKED! You can view this answer by clicking here to Register or Login and paying $3. If you've already paid for this answer, simply Login.

Just one question. Why is velocity not zero at time = zero (you start with value of one). Kindly clarify. You may be correct Just trying to understand. It is late here, unless you respond in next 5 minutes I will be able to view in my am. Thanks.

Since west is negative, velocity at t=0 is -1, and acceleration is -1. At time t=0, when one starts to observer the bus, it might already be moving. If it just starts at t=0, velocity in that case would be 0.

Just a side note to help you with further graphs, first find the one variable as an algebraic function of another variable , then just draw graphs for that function. Like, Equations of motion are v = u+at d = ut + ½ at²

We assume u = -1, a = -1, so v = -1 - t (straight line with slope -1, and cutting vertical axis at v=-1) d = -t - 0.5t² (parabola, in case you've encountered them, you'd soon)

I already accepted this a while ago but somehowthe system still shows this question unanswered. Hopefully this will help close this.

JustAnswer in the News:

Ask-a-doc Web sites: If you've got a quick question, you can try to get an answer from sites that say they have various specialists on hand to give quick answers... Justanswer.com.

JustAnswer.com...has seen a spike since October in legal questions from readers about layoffs, unemployment and severance.

Web sites like justanswer.com/legal ...leave nothing to chance.

Traffic on JustAnswer rose 14 percent...and had nearly 400,000 page views in 30 days...inquiries related to stress, high blood pressure, drinking and heart pain jumped 33 percent.

Tory Johnson, GMA Workplace Contributor, discusses work-from-home jobs, such as JustAnswer in which verified Experts answer people’s questions.

I will tell you that...the things you have to go through to be an Expert are quite rigorous.

What Customers are Saying:

Wonderful service, prompt, efficient, and accurate. Couldn't have asked for more. I cannot thank you enough for your help. Mary C.Freshfield, Liverpool, UK

Wonderful service, prompt, efficient, and accurate. Couldn't have asked for more. I cannot thank you enough for your help. Mary C.Freshfield, Liverpool, UK

This expert is wonderful. They truly know what they are talking about, and they actually care about you. They really helped put my nerves at ease. Thank you so much!!!!AlexLos Angeles, CA

Thank you for all your help. It is nice to know that this service is here for people like myself, who need answers fast and are not sure who to consult.GPHesperia, CA

I couldn't be more satisfied! This is the site I will always come to when I need a second opinion.JustinKernersville, NC

Just let me say that this encounter has been entirely professional and most helpful. I liked that I could ask additional questions and get answered in a very short turn around. EstherWoodstock, NY

Thank you so much for taking your time and knowledge to support my concerns. Not only did you answer my questions, you even took it a step further with replying with more pertinent information I needed to know. RobinElkton, Maryland

He answered my question promptly and gave me accurate, detailed information. If all of your experts are half as good, you have a great thing going here.DianeDallas, TX