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An F-15 supersonic fighter aircraft is in a rapid climb. At

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An F-15 supersonic fighter aircraft is in a rapid climb. At the instant it passes through a standard altitude of 25,000 ft, its time rate of change of altitude is 500 ft/s, which is by definition is the rate of climb. Corresponding to this rate of climb at 25,000 ft is a time rate of change of ambient pressure. Calculate this rate of change of pressure in units of pounds per square foot per second.
Hi there!

dp/dt = -ρ(hG)g(hG)[d(hG)/dt] = -1.0663 x 10^-3 x 32.1 x 500 = -17.1 lb/ft^2/s

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Customer: replied 6 years ago.
Is the 500 ft/s the same as [d(hG)/dt]?
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