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Category: Homework
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Experience:  BA (Hons) in Mathematics from Oxford University
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# I have 3 questions 1) find the magnitude and direction angle

### Resolved Question:

I have 3 questions:
1) find the magnitude and direction angle of vector v---- v= 8(cos135%i=sin135%j)

2) v= -4i-7j

3) v=12i +15j
Submitted: 6 years ago.
Category: Homework
Expert:  M Hasan replied 6 years ago.

Hi there!

1)

I am going to assume the that % sign implies degrees and = is meant to be a minus sign. So basically, v = 8(cos135°i - sin135°j)

Magnitude: ||v|| = √((8cos135°)^2 - (8sin135°)^2) = √64 = 8

Direction: arctan (-sin 135/cos 135) = 45° in a clockwise direction from the x - axis.

2)

Magnitude: √((-4)^2 + (-7)^2) = √65 = 8.06

Direction: arctan (-7/-4) = 60.3° in a clockwise direction from the x - axis.

3)

Magnitude: √((12)^2 + (15)^2) = √369 = 19.2

Direction: arctan (15/12) = 51.3° in an anticlockwise direction from the x - axis.

Let me know if your require further clarification. If not, please do not forget to click 'Accept'. Thanks!

M Hasan, Teacher
Category: Homework
Satisfied Customers: 1849
Experience: BA (Hons) in Mathematics from Oxford University
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Customer: replied 6 years ago.

question 1 was : v= 8(cos 135%i + sin 135% j)

Expert:  M Hasan replied 6 years ago.
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