How JustAnswer Works:

  • Ask an Expert
    Experts are full of valuable knowledge and are ready to help with any question. Credentials confirmed by a Fortune 500 verification firm.
  • Get a Professional Answer
    Via email, text message, or notification as you wait on our site.
    Ask follow up questions if you need to.
  • 100% Satisfaction Guarantee
    Rate the answer you receive.

Ask M Hasan Your Own Question

M Hasan
M Hasan, Teacher
Category: Homework
Satisfied Customers: 1849
Experience:  BA (Hons) in Mathematics from Oxford University
30103992
Type Your Homework Question Here...
M Hasan is online now
A new question is answered every 9 seconds

I have 3 questions 1) find the magnitude and direction angle

Resolved Question:

I have 3 questions:
1) find the magnitude and direction angle of vector v---- v= 8(cos135%i=sin135%j)

2) v= -4i-7j

3) v=12i +15j
Submitted: 6 years ago.
Category: Homework
Expert:  M Hasan replied 6 years ago.

Hi there!

 

1)

 

I am going to assume the that % sign implies degrees and = is meant to be a minus sign. So basically, v = 8(cos135°i - sin135°j)

 

Magnitude: ||v|| = √((8cos135°)^2 - (8sin135°)^2) = √64 = 8

Direction: arctan (-sin 135/cos 135) = 45° in a clockwise direction from the x - axis.

 

2)

 

Magnitude: √((-4)^2 + (-7)^2) = √65 = 8.06

Direction: arctan (-7/-4) = 60.3° in a clockwise direction from the x - axis.

 

3)

 

Magnitude: √((12)^2 + (15)^2) = √369 = 19.2

Direction: arctan (15/12) = 51.3° in an anticlockwise direction from the x - axis.

 

Let me know if your require further clarification. If not, please do not forget to click 'Accept'. Thanks!

 

 

 

 

M Hasan and 2 other Homework Specialists are ready to help you
Customer: replied 6 years ago.

question 1 was : v= 8(cos 135%i + sin 135% j)

Expert:  M Hasan replied 6 years ago.
THIS ANSWER IS LOCKED!
You can view this answer by clicking here to Register or Login and paying $3.
If you've already paid for this answer, simply Login.