Hi, I'd be happy to do this for you,
I can draw them out and scan in the image if you would like? Would you like me to draw H, Li, Be, B, C, N, O, F, Na, Mg and the ions they make?
Ok, give me 5 mins and I'll have the first five you asked for drawn. Let me know if they're ok.
Ok, I've done the first four. I'll attach as a picture below. Let me know if they're ok and I'll continue with the rest.
This is good but she wants it written out here is an example of the way she wants it
Chlorine cl has 17 atoms she came up with an answer like this
Cl)2e )8e )7e- ]+1=Cl-1 using these number 2 8 8- 18
Ok, so for the first four:
H) 1e will go to H) 0e ]+1
Li) 2e) 1e will go to Li) 2e ]+1
Mg) 2e) 8e) 2e) will go to Mg) 2e) 8e ]+2
F) 2e) 7e will go to F) 2e) 8e]-1
Is that how you need it?
Yes, Can you become my personal tutor.
yes I do have question about them Can you show me step by step how you got the answer
B) 2e) 3e ---- B) 2e]3+
Be) 2e)2e ---- Be) 2e]2+
N) 2e)5e ----- N) 2e) 8e]3+
Cl) 2e)8e)7e ---- Cl) 2e) 8e) 8e]1-
Ne) 2e) 8e ---- already has full outer shell and so won't form an ion
Next one is a funny one, as it doesn't usually form an ion. It can either form a 4+ ion or a 4- ion:
Si) 2e) 8e) 4e ---- Si) 2e) 8e) 8e]4-
Si) 2e) 8e) 4e ---- Si) 2e) 8e]4+
Quite difficult to form either of these ions though!
Hope that they're in the right format for your teacher. Are you ok with how to do them?
If you look at the sheet I sent you it shows you what is happening in each case. Your outer shells need to have 8 electrons in them (unless its the first shell which is 2 electrons) when you form a stable ion. So you either add or take electrons away - whichever is easiest. If it is closer to 8 than 0 then you add electrons to it, if it is closer to 0 than 8, take electrons away. You can see why there was a bit of trouble with silicon as it is just as close to 8 as it is to 0.
Just saw your other post:
Ok, using boron as an example:
It has two inner electrons and three outer electrons:
So write it as follows: B) 2e) 3e
When it forms an ion it is easier to lose 3 electrons than to gain 5, therefore take away the outer three electrons:
You are left with 2 electrons, but the atom has a charge now, and so we call it an ion. It has lost 3 electrons and so has 3 more protons than electrons now giving it a +3 charge:
B) 2e ]3+
Therefore I have written the charge after the electron shell arrangement as ]3+
Hope this helps, if I have answered your question then you can accept my answer, if you would like to have me as a tutor, then if you have any other chemistry questions, post them in the homework section as you did for this one, just put at the beginning of your title for the question: For David Scrafton, then ask your question.