Experts are full of valuable knowledge and are ready to help with any question. Credentials confirmed by a Fortune 500 verification firm.

Get a Professional Answer

Via email, text message, or notification as you wait on our site. Ask follow up questions if you need to.

100% Satisfaction Guarantee

Rate the answer you receive.

Ask Sarah Your Own Question

Sarah,
Tutor / Ex-Teacher

Category: Homework

Satisfied Customers: 113

Experience: Stanford physics degree, 10+ yrs tutoring multiple subjects for elementary through college students

2701855

Type Your Homework Question Here...

Sarah is online now

PLANE TRIGONOMETRY PART 3

Resolved Question:

1)FIND THE SINE, CONSINE, TANGENT, AND COTANGENT OF: a)122 DEGREES b)315 DEGREES 12' c)275 DEGREES 13' 37" d)193 DEGREES 41' 51"
2)USING EXACT VALUES, FIND THE NUMERICAL VALUE OF: a)sin 30 DEGREES cos 240 DEGREES +sin 210 DEGREES sin 300 DEGREES b)tan 225 DEGREES + tan (-45 DEGREES)
3)EXPRESS EACH OF THE FOLLOWING AS THE SAME FUNCTION OF A POSITIVE ACUTE ANGLE: a)cos 112 DEGREES 33' b)tan 310 DEGREES c)cot 138 DEGREES 15' 10" d)sin (-140 DEGREES)4)EXPRESS EACH AS A FUNCTION OF 0:a)sin (270 DEGREES + 0) b)cos (pi + 0) c)tan (810 DEGREES + 0) d)sin (0-180 DEGREES)5)FIND THE VALUE OF: a)log sin 62 DEGREES 22' 33" b)log cot 28 DEGREES 13' 17" c)log cos 125 DEGREES 15' 23" d)log tan 78 DEGREES 45' 50" 6)FIND THE ACUTE ANGLE A, TO THE NEAREST SECOND, WHEN: a)log cos A=9.12575 b)log sin A=9.91655 c)log cot A=0.11975 d)log tan A=0.063237)SIMPLIFY: sin(90 DEGREES+x)sin (180 DEGREES+x)cos(90 DEGREES+x)cos(180 DEGREES-x) 8)SOLVE THE RIGHT TRIANGLE BY LOGARITHMS:A=28 DEGREES 30', b=18.3

I am not entirely sure what this is asking. The problems as stated already are functions of 0 technically, and you could write each answer in various different ways incorporating 0....

c)log cos 125 DEGREES 15' 23" = No answer, because cos 125 is a negative number and you can't take log of a negative number.

d)log tan 78 DEGREES 45' 50" = 0.702

6)FIND THE ACUTE ANGLE A, TO THE NEAREST SECOND, WHEN:

There are no solutions to (a) or (b) as I understand the problem - as you can see in the work below, finding A is out of the domain range because cos of any angle could never equal 10^{9.12575} - a number much much bigger than 1. Am I misreading the problem? I believe this is log_{10}(cosA) = 9.12575. Is this correct??? Please email me back and we will see if we can figure this out.

i also need more answers,
solve the following oblique triangles 9)a = 31,b = 15, c = 17
10)a = 23.47, b = 115 degrees 30', c= 20 degrees 29' 11)a = 134.2,b = 84.54, B = 52 degrees 9' 11" 12)a = 627.7, b = 412.2, A = 66 degrees 47'

THIS ANSWER IS LOCKED! You can view this answer by clicking here to Register or Login and paying $3. If you've already paid for this answer, simply Login.

Ask-a-doc Web sites: If you've got a quick question, you can try to get an answer from sites that say they have various specialists on hand to give quick answers... Justanswer.com.

JustAnswer.com...has seen a spike since October in legal questions from readers about layoffs, unemployment and severance.

Web sites like justanswer.com/legal ...leave nothing to chance.

Traffic on JustAnswer rose 14 percent...and had nearly 400,000 page views in 30 days...inquiries related to stress, high blood pressure, drinking and heart pain jumped 33 percent.

Tory Johnson, GMA Workplace Contributor, discusses work-from-home jobs, such as JustAnswer in which verified Experts answer people’s questions.

I will tell you that...the things you have to go through to be an Expert are quite rigorous.

What Customers are Saying:

Wonderful service, prompt, efficient, and accurate. Couldn't have asked for more. I cannot thank you enough for your help. Mary C.Freshfield, Liverpool, UK

Wonderful service, prompt, efficient, and accurate. Couldn't have asked for more. I cannot thank you enough for your help. Mary C.Freshfield, Liverpool, UK

This expert is wonderful. They truly know what they are talking about, and they actually care about you. They really helped put my nerves at ease. Thank you so much!!!!AlexLos Angeles, CA

Thank you for all your help. It is nice to know that this service is here for people like myself, who need answers fast and are not sure who to consult.GPHesperia, CA

I couldn't be more satisfied! This is the site I will always come to when I need a second opinion.JustinKernersville, NC

Just let me say that this encounter has been entirely professional and most helpful. I liked that I could ask additional questions and get answered in a very short turn around. EstherWoodstock, NY

Thank you so much for taking your time and knowledge to support my concerns. Not only did you answer my questions, you even took it a step further with replying with more pertinent information I needed to know. RobinElkton, Maryland

He answered my question promptly and gave me accurate, detailed information. If all of your experts are half as good, you have a great thing going here.DianeDallas, TX