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RoberttheRocket, Teacher/tutor
Category: Homework
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# Math Questions

Please clarify question 13. There seems to be an overprinting of 96/8 on top of sqrt (27). In problem 14, you need to provide the expression to be simplified --- only the multiple choices are there. I have answers to the other questions ready.

Aside from questions 13 and 14, which you need to clarify (see my previous free post), the answers are as follows:

1 C. 2C. 3D. 4D. 5A. 6A. 7A. 8A. 9C

10D. 11B. 12D. 13? 14? 15A. 16D. 17B. 18A. 19B. 20C.

Answers to 13 and 14 can be provided after you have restated those questions clearly. I await your response on that.

1 C  2 C  3 D  4 B  5 A  6 B  7 A  8 A  9 C  10 C  11 B

12 D  13 A  14C  15A  16 D  17 C  18 A  19 B  20 C

1. C ab

2. C.

4/x^2 [(6x^3)/(3x^4)]^2 = (2/x)^2 = 4/x^2

3. D.

25 2Vx + 20 = 15 + 3Vx

2Vx + 20 - 15 = 15 + 3Vx - 15

2Vx + 5 = 3Vx

2Vx + 5 - 2Vx = 3Vx - 2Vx

5 = Vx

(5)^2 = (Vx)^2

25 = x

4. B. 4

V(x) + 5 = V[x + 45]

Square both sides

{V[x] + 5}^2 = {V[x + 45]}^2

x + 10V[x] + 25 = x + 45

x + 10V[x] + 25 - x - 25 = x + 45 - x - 25

10V[x] = 20

Square both sides

(10V[x])^2 = (20)^2

100x = 400

(100x)/100 = 400/100

x = 4

5. A. (s^4)(t^4)/(r^5)

(r^-3s^5t^2)/(r^2st^-2)

= (r^-3)(r^-2)(s^5)(s^-1)(t^2)(t^2)

= (r^-5)(s^4)(t^4)

= (s^4)(t^4)/(r^5)

6. B.

.0003532 = 3.532 * 10 * ^-4

7. A.

34392.55 = 3.439255 * 10^4

8. A.

.000938 = 9.38 * 10^-4

9. C.

10. C.

6V[2]/V[3]

= (6V[2]) (V[3]) / (V[3])(V[3])

= (6V[6]) / 3

= (2V[6])

11. B.

V[18x^4y^3] =

V[2*3^2*x^4*y^3] =

(3)(x^2)(y)V[2*y]

12. D.

2V20 - 3V7 - 2V5 + 4V63

= 2V[4*5] - 3V[7] - 2V[5] + 4V[9*7]

= (2)(2)V[5] - 3V[7] - 2V[5] + (4)(3)V[*7]

= 4V[5] - 3V[7] - 2V[5] + 12V[7]

= 2V[5] + 9V[7]

13. A.

2 times the square root of 27 times 3 times the square root of 32.

2V27 * 3V32

2V[9*3] * 3V[16*2]

(2)(3)V[3] * (3)(4)V2

6V[3] * 12V[2]

72[6]

14. C.

If it is asking for the square root of the fraction 96/8

V[96/8]

V[12)

2V[3]

15. A.

V[64/100] = 8/10 = 4/5

16. D.

V[9x^2] / V[18y^2]

= 3x / 3yV[2]

= (3x)(V[2]) / (3yV[2])(V2[])

= (3x)(V[2]) / (3y)(2)

= (3x)(V[2]) / (6y)

= (x)(V[2]) / (2y)

17. C.

V[j] + V[j] + 14 = (3)V[j} + 10

2V[j] + 14 = (3)V[j} + 10

2V[j] + 14 - 2V[j] = (3)V[j} + 10 - 2V[j]

14 = V[j] + 10

14 - 10 = V[j] + 10 - 10

4 = V[j]

square both sides

(4)^2 = (V[j])^2

16 = j

18. A.

c^2 = a^2 + b^2

c^2 = 3^2 + 6^2

c^2 = 9 + 36

c^2 = 45

c = 3V[5]

19. B.

c^2 = a^2 + b^2

20^2 = 15^2 + b^2

400 = 225 + b^2

400 - 225 = 225 + b^2 - 225

175 = b^2

take the square root of both sides

V[175] = V[b^2]

V[25*7} = b

5V[7] = b

20. C.

c^2 = a^2 + b^2

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^2 = 52

take the square root of both sides

c = V[52]

Customer: replied 11 years ago.

13. Simplify the expression (2√27) • (3√32)

14. Simplify the expression √96/8

1 C  2 C  3 D  4 B  5 A  6 B  7 A  8 A  9 C  10 C  11 B

12 D  13 A  14C  15A  16 D  17 C  18 A  19 B  20 C

13. A

for 14. C

14. Simplify the expression ã[96/8]

V[96]/8 = V[16*6/8]  = V[2 * 6] = V[12] = V[4 * 3]

= 2V[3]

C. the square root of [96 divided by 8] is  2V3 (two times the square root of 3.).

V[96]/8  = V[16*6]/8]  =  4V[6] /8  = V[6] /2

The square root of [96], divide that by 8 is V[6] /2  (the square root of [6], divided by 2. and you don't have this answer.

RoberttheRocket, Teacher/tutor
Category: Homework
Satisfied Customers: 119
Experience: A teacher since 1977 and web savvy.

In my haste to answer first,  I made 4 errors out of 20 which RoberttheRocket later answered correctly. In some cases, I did the math right and copied the choice wrong. I also agree with his selections for the recently restated questions #13 and #14.  Robert deserves to be the accepted answerer here. I goofed.

13.  2 sqrt 7 x 3 sqrt 32 = 2 sqrt (9*3) x 3 sqrt (16*2)

= 6 *3*4 * sqrt (3*2) = 72 sqrt 6  (A)

14. sqrt (96/8) = sqrt (8*12/8) = sqrt 12 = sqrt (4*3)

= 2 sqrt 3  (C)

Customer: replied 11 years ago.

Hello Dr WLS,

Thank you very very much for your help .you are really great person.

Thanks

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