Recent Feedback
A 0.041 kg aluminum bullet traveling at 407 m/s strikes an armor plate and comes to a stop. If all its energy is converted to heat that is absorbed by the bullet, what is the bullet's temperature change in degrees Celsius?
Hello, welcome to JustAnswer.This one is just like the one you asked with the 489 m/s.We first need to find the kinetic energy in the bullet just before the impact.Q = (1/2)*mvˆ2 = 0.5 * 0.058 * 407ˆ2 = 4803.82 JouleSpecific heat (c) of aluminum is 900 J(Kg*degree_Celcius)The temperature delta = Q/(mc) = 4803.82/(0.041*900) = 130.185 Celcius.
Experience: i'm 35 and i never stopped studying and experimenting