2x^2 + 5x + 5 = 0
using the ax^2 + bx + c = 0 form and applying it to the equation in question, we find thata = 2b = 5c = 5
now substituting a, b and c in the quadratic root equation
you find there are no real solutions to th equation because the expression (b^2-4ac) is 25-40=-15 which is negative.
Hope this helps.
Was there anything else you needed? If you have any questions please let me know.