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xarqi, Generalist
Category: General
Satisfied Customers: 596
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# chemisry

### Customer Question

i have some data
A) Charle's Law
Data:      Volume - Temperature Pairs
8.9cm       30c
9.1cm       40c
9.2cm       50c
9.5cm       60c
9.65cm      70c
9.8cm       80c
I have to graph them and Least Sqaure calculations T (degrees centigrade) at absolute zero.
in order to do that, i have to prepare a graph in which i polot V against T in Celcius degree. This plot should show a linear relationship of the form V=aT +b. Use the least squares method to find the slope (a) and the y intercept (b) for this equation. Absolute zero on the Celcius scale will be the temperature at which V falls to zero: this temperature can be found by using the equation
T of absolute zero in celcius degree = -b/a
Submitted: 11 years ago.
Category: General
Expert:  xarqi replied 11 years ago.
I have your graph, but I can no longer insert it here as the maximum
image size has been cut from 200K to 25k(!).  That is totally
nuts, so I'll enquire with the JA management.  If you supply an
email address I can send it to you that way.

Your equation is V = 0.0184T + 8.3448, and when it is applied to
calculate absolute zero, the answer is -453 °.  This is clearly
nonsense, since the figure should be about -273°.  It is however
very close to the value for absolute zero in Fahrenheit (-459 °).
Have you got your temperature scales right?

xarqi, Generalist
Category: General
Satisfied Customers: 596
Experience:
Expert:  xarqi replied 11 years ago.
OK - the image glitch has been fixed, so here it is.

xarqi, Generalist
Category: General
Satisfied Customers: 596
Experience:
Customer: replied 11 years ago.
Reply to xarqi's Post: ok, thank you
could you answer me the another question that i posted? it is chemistry gas laws.

Thanks
Customer: replied 11 years ago.
how did you get the answer -453?
Expert:  xarqi replied 11 years ago.
-b/a

-8.3448/0.0184 = -453.5
Expert:  xarqi replied 11 years ago.
the volume increase in a fixed quantity of gas?

If you did, the 30 ° sounds a lot like the temperature you'd start
with in Fahrenheit.
Customer: replied 11 years ago.
how did you get the 0.0184 and 8.3448?

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