1) Thank you for the replies Anthony.
2) Applying Watts Law where P = I x E, solve for I. 4800 watts = I x 240 volts, therefore I = 4800/240 = 20 amps
3) Therefore you will need a 20 amp double pole breaker using 12 AWG copper. Code now requires range circuits to be a 4 wire circuit. You will need 12/3 Romex with a ground (total of 4 wires).
4) The voltage drop using 12 feet, 20 amps and 240 volts = .4 %. Code recommends a maximum VD % of 3%, therefore you are good to go on the wire size.
5) The 12/3 AWG Romex will terminate as follows: The black will terminate on one side of the 20 amp breaker, the red will terminate on the other side of the 20 amp breaker, the white will terminate onto the neutral bus bar in the panel and the bare copper will terminate onto an equipment ground bar inside the panel. The white does not land on the breaker, it will land on the neutral bus bar. You will require a NEMA 14-20R receptacle and a NEMA 14-20P plug.
Hope this helps.........If you have any additional questions, let me know and I'll be glad to answer them for you.
Otherwise, don't forget to rate me before you log Off.
The next time you have an electrical question, you can also request for me at: http://www.justanswer.com/home-improvement/expert-your-electrician