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General lighting load is 3 watts per square foot. For 2 wire branch circuits we need to use the lighting load and add the 2 small appliance circuits, the laundry, the bathroom. 3 circuits are required for the lighting load since 3 watts X 1800 = 5400 and this equals 3 15 amp circuits at 1800 watts each. The minimum total circuits required is therefore 7 circuits.
I'll work at #3 now for you. This will take longer.
Small Appliance circuits 2 @ 2400 va laundry 1 @ 2400 bathroom 1 @ 2400 general lighting 5400 totals 15,000 va
Range at 11 kw is calculated at 8 kw and the dryer at nameplate or 6.4 kw.
Your example does not include a bathroom but one is required by code. This confuses the issue here.
The 15,000 va is adjusted using 3000 va at 100% and the remaining 12,000 va at 35% or 4200 va. We therefore have 7200 va in general lighting and receptacle loads. Add to this the 8,000 for the range and 6,400 for the dryer and we have 21,600 va when divided by 240 volts gives us 90 amperes. This would require at least a 100 amp service.
For example #2 the heat pump of 25 amps would be equal to 6000 va or 6 kva. General lighting load is 2200 X 3 = 6600 va.
Lighting load 6600 va, small appliance load 4800 va, laundry 2400, bathroom 2400 totals 16,200 va
3000 at 100% and 13,200 at 35% totals 7620 va.
There are only 3 appliances, not 4, that would be considered when looking to apply the 75% factor to additional applainces so that will not apply. They will be taken at 100%
Range again is taken at 8 kva, water heater at 5 kva, dishwasher, compactor at 1.5 kva and 1.3 kva respectively. Baseboard heat of 18 kva is taken at 100% as well. This will give us a total load of 47,420 va. including the heat pump. If this was air conditioning instead of a heat pump it would not be used at the same time as the baseboard heating so only the larger would be considered.
47,420 va = 197.58 amperes or a 200 amp service.