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a. Number of blocks per track:Size of block = 10*160 bytes = 1600 bytes1 track can hold = 19000 bytesso no. of blocks per track will be = 19000/1600 = 11.875(approx 11)b. Waste per track:Data that can be stored on 1 track is = 19000 BytesBut block size is fixed = 1600 bytesSo only 11 blocks can be saved = 1600*11 = 17600 bytesremaining all gets wastedso Waste per track will be = 19000 - 17600 = 1400 bytesc. Number of tracks required to store the entire file:Total number of records to be stored = 2000001 record size = 160 bytesso total required space will be = 200000*160 = 32000000 bytesTrack size is = 19000 bytesSo, No of tracks required will be = 32000000/19000 = 1684.21 (1685 approx)d. Total waste to store the entire file:waste per track was = 1400 bytes.waste per 1685 track will be = 1400*1685 =(NNN) NNN-NNNNbytese. Time to write all of the blocks:Total no. of blocks are = 1685 * 11 = 18535will be written at the rate of .1ms/trackand total no of track are 1685 so time taken will be = 1685*0.1 = 168.5 msh. answer will be = 1685*0.2 = 337 ms