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Hirash Riyal, Computer Software Engineer
Category: Programming
Satisfied Customers: 184
Experience:  BIT Finalist, DIPLOMA IN IT,DOPLOMA IN PROGTAMMING,
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# write a program that takes the length and width of a rectangular

### Customer Question

write a program that takes the length and width of a rectangular yard and the length and width of a rectangular house situated in the yard. Your program should compute the time required to cut the grass at the rate of two square feet a second.
Submitted: 7 years ago.
Category: Programming
Expert:  Kendall replied 7 years ago.

First compute the area of the entire yard (L * W = A1). Then take the area of the house (HL * HW = A2). The yards area would then be A2 - A1 = YardArea.

If A1 = 5000 sq/ft and A2 = 2000 sq/ft then the yard's area would be (A2 - A1) or 3000 sq/ft.

If you can cut the grass at a rate of 2 sq ft a second then simply divide the yards area by 2. (i.e. 3000 / 2 = 1500 seconds or 25 minutes).

Customer: replied 7 years ago.
I need the specifics to write it into a C program. This is my first homework assignment and I am not understanding the syntax.
Expert:  Kendall replied 7 years ago.

Yes, the specifics of the assignment will definitely help other experts assist you. So, its a C program. I can't write the program for you. However, you should have some text books (and internet) which should give you adequate instructions on obtaining values from user input (i.e. cin).

I apologize as I can't help much from this point forward. I'm no expert in C. My primary area of expertise is VB.Net. Good Luck.

Customer: replied 7 years ago.
thank you anyway
Expert:  Hirash Riyal replied 7 years ago.
Hi,

Expert:  Hirash Riyal replied 7 years ago.
hi,
following is the code
//code starts here
#include<stdlib.h>
#include<stdio.h>
#include<conio.h>
long YardArea=0,HouseArea=0;
int YardLength=0,YardWidth=0,HouseLength=0,HouseWidth=0;
long GroundArea=0;
int TimeReqierd=0;
int GrassCutRate=2;
void main()
{
char inp[256];
clrscr();
printf("******Welcome To Grass Cutter******\n");
printf("please Enter the Length of Yard\n");
gets(inp);
YardLength= atoi(inp);
printf("please Enter the Width of Yard\n");
gets(inp);
YardWidth=atoi(inp);
printf("please Enter the Length of House\n");
gets(inp);
HouseLength=atoi(inp);
printf("please Enter the Width of House\n");
gets(inp);
HouseWidth=atoi(inp);
HouseArea=HouseWidth *HouseLength ;
YardArea=YardWidth* YardLength;
GroundArea=YardArea-HouseArea;
TimeReqierd=GroundArea/GrassCutRate;
printf("%s%d","Grass Area is ",GroundArea);
printf("%s%d seconds"," \n time Required To cut it is " ,TimeReqierd);
getchar();
}
//code ends here
Hirash Riyal, Computer Software Engineer
Category: Programming
Satisfied Customers: 184
Experience: BIT Finalist, DIPLOMA IN IT,DOPLOMA IN PROGTAMMING,

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