Hello, I'm Jason. I will do my best to answer your question quickly and accurately using the information you have provided.
The centripetal force is only equal to the static frictional force to a point, that point being where the tires lose adhesion...
in most cases of regular road cars, this force is going to be about .80-.90g
the opposite force is going to be centrifugal force, meaning a vector pointing from the apex of the corner, outward
I'd like to keep this chat open, if you're able to access it, otherwise I'll change to standard email format
please let me know if you have further questions. Switching formats now
When you say that the tires loose adhesion at 0.8-0.9 grams, (Is it grams?) where are you getting numbers? Do they relate to vectors pointing out from the center of the circle? Is that how people find the coefficients for static and kinetic friction?