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Ashok Kumar, Electrical Engineer

Category: Calculus and Above

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Experience: Masters Degree in Electrical Engineering

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In a survey of 616 males ages 18-64, 392 say they have

Customer Question

In a survey of 616 males ages 18-64, 392 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.

Here p = 392/616 = 0.6363 standard deviation = sqrt[p(1-p)/n] = sqrt(0.6363*0.3636/616) = 0.01938 Confidence interval: p±z*standard deviation For 90% confidence interval, z = 1.645 Hence, 90% confidence interval: (0.6363±1.645*0.01938) : (0.6044, 0.6682) For 95% confidence interval, z = 1.96 Hence, 95% confidence interval: (0.6363±1.96*0.01938) : (0.5983, 0.6743) 90% confidence interval means that 90 times out of 100, the probability will be between 0.6044 and 0.6682. Similarly 95% confidence means. 95% confidence interval is wider. Kindly rate the answers.