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SusanAthena, Master's Degree

Category: Calculus and Above

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Yes I have a test that is due today and I noticed you answered

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yes I have a test that is due today and I noticed you answered most of the questions for someone else....how does this work

Submitted: 1 year ago.

Category: Calculus and Above

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Given the linear correlation coefficient r and the sample size n, determine the critical values of r and use your finding to state whether or not the given r represents a significant linear correlation. Use a significance level of 0.05. r = 0.75, n = 9 Critical values: r = ±0.666, no significant linear correlation Critical values: r = 0.666, no significant linear correlation Critical values: r = -0.666, no significant linear correlation Critical values: r = ±0.666, significant linear correlation 5 points Question 2 Construct a scatterplot for the given data. Choose A, B, C, or D. 5 points Question 3 Find the value of the linear correlation coefficient r. -0.054 0.214 0.109 -0.078 5 points Question 4 Suppose you will perform a test to determine whether there is sufficient evidence to support a claim of a linear correlation between two variables. Find the critical values of r given the number of pairs of data n and the significance level alpha. n = 11, = 0.01 r = 0.765 r = ± 0.602 r = 0.735 r = ± 0.735 5 points Question 5 Use the given data to find the best predicted value of the response variable. Six pairs of data yield r = 0.789 and the regression equation What is the best predicted value of y for x = 5? 22.0 18.0 18.5 19.0 5 points Question 6 Use the given data to find the equation of the regression line. Round the final values to three significant digits, if necessary. Choose A, B, C, or D. 5 points Question 7 Is the data point, P, an outlier, an influential point, both, or neither? Neither Outlier Both Influential point 5 points Question 8 Use the given information to find the coefficient of determination. A regression equation is obtained for a collection of paired data. It is found that the total variation is 24.488, the explained variation is 15.405, and the unexplained variation is 9.083. Find the coefficient of determination. 0.629 0.590 1.590 0.371 5 points Question 9 Use the computer display to answer the question. 82.7% 17.0% 91.1% 83.0% 5 points Question 10 Find the explained variation for the paired data. The paired data below consists of test scores and hours of preparation for 5 randomly selected students. The equation of the regression line is = 44.8447 + 3.52427x. Find the explained variation. 498.103 511.724 87.4757 599.2 5 points Question 11 Find the unexplained variation for the paired data. The paired data below consists of test scores and hours of preparation for 5 randomly selected students. The equation of the regression line is = 44.8447 + 3.52427x. Find the unexplained variation. 511.724 87.4757 96.103 599.2 5 points Question 12 Find the total variation for the paired data. The paired data below consists of test scores and hours of preparation for 5 randomly selected students. The equation of the regression line is = 44.8447 + 3.52427x. Find the total variation. 599.2 498.103 511.724 87.4757 5 points Question 13 Find the standard error of estimate for the paired data. The paired data below consists of test scores and hours of preparation for 5 randomly selected students. The equation of the regression line is = 44.8447 + 3.52427x. Find the the standard error of estimate. 4.1097 7.1720 5.3999 13.060 5 points Question 14 Construct the indicated prediction interval for an individual y. The paired data below consists of test scores and hours of preparation for 5 randomly selected students. The equation of the regression line is = 44.845 + 3.524x and the standard error of estimate is Se = 5.40. Find the 99% prediction interval for the test score of a person who spent 7 hours preparing for the test. 58 < y < 82 62 < y < 78 35 < y < 104 32 < y < 107 5 points Question 15 Solve the problem. 1.936 < B1 < 4.874 0.686 < B1 < 6.124 0.322 < B1 < 6.488 0.134 < B1 < 6.676 5 points Question 16 Use computer software to find the multiple regression equation. Can the equation be used for prediction? An anti-smoking group used data in the table to relate the carbon monoxide of various brands of cigarettes to their tar and nicotine content. CO = 1.37 - 5.53TAR + 1.33NIC; Yes, because the R2 is high CO = 1.37 + 5.50TAR - 1.38NIC; Yes, because the P-value is high CO = 1.3 + 5.5TAR - 1.3NIC; Yes, because the adjusted R2 is high CO = 1.25 + 1.55TAR - 5.79NIC; Yes, because the P-value is too low 5 points Question 17 Use computer software to obtain the multiple regression equation and identify R2, adjusted R2, and the P-value. An anti-smoking group used data in the table to relate the carbon monoxide of various brands of cigarettes to their tar and nicotine content. 0.976, 0.921, 0.002 0.943, 0.934, 0.000 0.931, 0.902, 0.000 0.861, 0.900, 0.015 5 points Question

Hi there! Thank you for requesting me (I am trigeoscal or aka Mr. Glenn) Can I help you? What time or how many hours/minutes do you need the answers? I am now working on these. By the way, you forgot to include the actual data for Q2, Q3 Q6, Q7 and Q9 kindly sent them (the complete data) so that I can now answer those questions or better, kindly attach and send the actual questions in word or excel format/file including the complete data. Please reply Regards, Mr. Glenn G. (Trigeoscal) ************************************************* You can request me in future by writing "For Mr. Glenn G. only".

Hi there! By the way, you forgot to include the actual data for Q2, Q3 Q6, Q7 and Q9 kindly sent them (the complete data) so that I can now answer those questions or better, kindly attach and send the actual questions in word or excel format/file including the complete data. Please reply Regards, Mr. Glenn G. (Trigeoscal) ************************************************* You can request me in future by writing "For Mr. Glenn G. only".