i have to pay $45 for answering one question?
so I can pay at the end of all my questions? Ill gladly pay $45. But I have 19 more to go. If not worth your time let me know. If it is here is the next question.
Construct the confidence interval for the population
c=0.90, x=8.1 s=0.2 and n=53
Final answer works...
construct the confidence interval for population. Round to one decimal place as needed.
c=0.95, x (x has line over it)=15.9 , s=4.0, and n=70
please adjust for a 95% confidence interval for u is? round to one decimal place
use the confidence interval to find the estimated margin of error. Then find the sample mean.
a biologist reports a confidence interval of (4.7,5.1) when estimating the mean height (in centimeters) of a sample of seedlings
The estimated margin of error is?
Q 7 of 20
Find the minimum sample size n needed to estimate u for the given values of c,s, and E.
Assume that a preliminary sample of has at least 30 members
n=? (round up to the nearest whole number)
q9 of 20 ( i will give you max tip as well hang in there lol)
you are given the sample mean and the sample standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If convienient, use technology to construct the confidence intervals.
A random sample of 44 gas grills has a mean price of $646.30 and a standard deviation of $57.20.
The 90% confidence interval is? (round to two decimal places as needed)
FYI 95% interval was not correct...
q10 of 20
You are given the sample mean and teh sample sandard deviation.Use this information to construct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If convenient, use the technology to construct the confidence intervals.
A random sample pf 32 eight ounce servings of different juice drinks has a mean of 76.6 calories and a standard deviation of 45.2 calories.
The 90% confidence interval is ? (round to one decimal place as needed)
People were polled on how many books they read the previous year. How many subjects are needed to estimate the number of books read the previous year within one book with 90% confidence? The intial survey results indicate that O (looks kind of like an o symbol) o=13.9 books.
A 90% confidence level requires blank subjects
q12 of 20
A doctor wants to estimate the HDLcholesterol of all 20- to 29 year old females. How many subjects are needed to estimate the HDL cholesterol within 2 points with 99% confidence assuming o=13.1? Suppose the doctor would be content with 90% confidence. How does the degrease in confiendence affect the sample size required?
A 99% confidence level requires Blank subjects
pls add the 90% confidence level for q12
q13 of 20
Construct the indicated confidence interval for the population mean u using (a) a t-distribution. (b) if you had a incorrectly used a normal distribution, which interval would be wider?
c=0.95, x (with line over it) x=13.3, s=3.0 n=10
(a) the 95% confidence interval using a t distribution is? ( round to one decimal place as needed)
q14 of 20
In the following situation, assume the random variable is normally distributed and use a normal distribution or a t-distribution to construct a 90% confidence interval for the population mean. If convenient, use technology to construct the confidence interval.
(a) in a random sample of 10 adults from a near by county, the mean waste generated per person per days was 5.26 punds and the standard deviation was 1.79 pounds.
(b) Repeat part 9a), assuming the same statistics came from a sample size of 600. Compare the results.
(a) for the sample of 10 adults, the 90% confidence interval is ? 9round to two decimal places as needed)
b was wrong not sure if you based if of 600.
q15 of 20
Use the given confidence interval to find the margin of error and the sample proportion
E=blank (type an interger or a decimal)
q16 of 20
In a survey of 626 males ages 18-64, 391 say they have gone to the dentist in the past year.
Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.
The 90% confidence interval for the population proportion p is? (round the final answers to the nearest thousandth as needed. Round all intermediate values to the nearest thousandth as needed)
q17 of 20
In a survey of 6000 women, 3431 say they change their nail polish once a week. Construct a 99% confidence interval for the population proportion of women who change their nail polish once a week.
A 99% confidence interval for the population proportion is? Round to the nearsest thousandth
q18 of 20
A researcher wishes to estimate, with 90% confidence the proportion of adults who have high speed internet access. her estimate must be accurate within 1% of the true proportion.
(a) find the minimum sample size needed, using a prior student that found that 52% of the respondents said they have high speed internet access.
(b) No preliminary estimate is available. Find the minimum sample size needed.
a) what is the minimum sample size needed using a prior study that found that %52 of the respondents said they have highspeed internet access?
n=? round up to the nearest whole number as needed