Solve the following by the method of variation of parameter.1) y'' + y = sec(theta) * tan(theta)2)y'' - y cosh(x)3) y'' - 2y' + y = e^(x) / (1 + x^(2))4) 3y'' - 6y' + 6y = e^(x) * sec(x)Solve the following using the method of undetermined coefficients1) y'' - 8y' +20y = 100x^(2) - 26xe^(x)2) y'' - 4y = ((x^2) - 2) * sin(2x)3) y'' - 2y' +2y = e^(2x) * (cos(x) - 3sin(x))4) y'' + 2y' - 25y = 16 - (x+2) * e^(4x)
There are 7 equations in total to be solved. I suggest splitting of this order in three orders.
actually is there any way to close this order?
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