f(X)=（x³+2x）e^x ；y=e^ax³；y=e^-2t cos4t；f(t)=sin(e^t)+e^sint;y=e^u-e^-u/e^u+e^-u;y=√1+xe^-2xDifferentiate the function.Sorry i am not good at math.
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Welcome and Thanks for requesting me.
There are 6 problems in all right? Need only answers? Let me know.
Thanks.
NO,I need every answer for every problem. Thank you. I am not good at math.
You need working steps for each problem? Or only the final answers for each?
y=e^-2t cos4t；f(t)=sin(e^t)+e^sint;y=e^u-e^-u/e^u+e^-u;y=√1+xe^-2x;
I need those questions answer , if you have step for each problem that is better. Thank you. Just four questions.
Ok, I am working on your questions and will post the answers shortly.
(1) f'(x) = (x^3 + 2x) e^x + (e^x)(3x^2 + 2)
= (e^x) (x^3 + 3x^2 + 2x + 2)
(2) y = (e^(ax^3)) a(3x^2)
= (3ax^2) e^(ax^3)
(3) y' = (e^-2t)(-4 sin 4t) + (cos 4t)(-2 e^-2t)
= (e^-2t)(-4 sin 4t - 2 cos 4t)
(4) f'(t) = (cos e^t) e^t + (e^(sin t)) cos t
(5) y' = [(e^u + e^-u)(e^u + e^-u) - (e^u - e^-u)(e^u - e^-u)] / (e^u + e^-u)^2
= 4 /(e^u + e^-u)^2
(6) y' = [1/2 √(1 + xe^-2x)] [x(-2e^-2x) + (e^-2x)]
= (e^-2x)(1 - 2x) / [2 √(1 + xe^-2x)]
I hope that helps. Let me know if you need any clarifications on my answers. I will be happy to provide them. Else, please give a rating for my answer.
Experience: I have a Master's degree in Engineering and a very wide teaching experience of more than 25 years at various levels.