Here are the answers
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.
n = 125, x = 72; 90% confidence
0.507 < p < 0.645 0.503 < p < 0.649
0.506 < p < 0.646
0.502 < p < 0.650
Solve the problem. Round the point estimate to the nearest thousandth.
50 people are selected randomly from a certain population and it is found that 13 people in the sample are over 6 feet tall. What is the point estimate of the proportion of people in the population who are over 6 feet tall?
Use the confidence level and sample data to find a confidence interval for estimating the population (mu). Round your answer to the same number of decimal places as the sample mean.
A random sample of 130 full-grown lobsters had a mean weight of 21 ounces and a standard deviation of 3.0 ounces. Construct a 98% confidence interval for the population mean mu.
21 oz < mu < 23 oz 20 oz < mu < 22 oz
20 oz < mu < 23 oz
19 oz < mu < 21 oz
Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value used to test a null hypothesis.
a= 0.05 for a left-tailed test.
Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).
The test statistic in a right-tailed test is z = 1.43. (Points : 4)
0.1528; fail to reject the null hypothesis
0.1528; reject the null hypothesis 0.0764; fail to reject the null hypothesis
0.0764; reject the null hypothesisBonus is welcome