ok I presume it is inches instead of feet on the sheave. Give me a few minuits and Ill be back
For the 14" sheave the shaft RPS's will be 0.64285714285714285714285714285714:1
So we take that number and and make it a fraction which equals 0.64285714285714285714285714285714/100, or 0.64285714285714285714285714285714% of 1750.
Now devide 1750 by 0.64285714285714285714285714285714% and we get 11.249999999999999999999999999998.
Move the decimal 2 places to the right, and you have 1124.9999999999999999999999999998 RPMs at the end sheave.
Or 625.000000000000000000000000001RPMS less than the 9" input pully
For the 16" sheave the shaft RPM's will be 0.5625:1 Which ends up being 0.5625%
Devide 1750 by 0.5625% = 9.84375 Move decimal = 984.375 RPM's at end sheave.
So the out puts for a 14" shaft are 1125 RPM and for the 16" shaft they are 983 RPM's.
Thank you again for the accept.
Please be sure to leave poositive feedback and any bonuses are always welcome.
Best regards; The Home Smithy